Let's work through Energy — Complete Guide with Examples together. Physics problems become simple when you break them into clear, logical steps. Here's exactly how to approach this one.
See the step-by-step solution above for the complete answer.
Step 1: KE = ½mv²
Step 2: KE = ½ × 2 × 6² = ½ × 2 × 36 = 36 J
Step 3: KE = ½mv²
Step 4: KE = ½ × 2 × 6² = ½ × 2 × 36 = 36 J
Step 5: KE = ½mv²
Step 6: KE = ½ × 4 × 9² = ½ × 4 × 81 = 162 J
Step 7: KE = ½mv²
Step 8: KE = ½ × 6 × 12² = ½ × 6 × 144 = 432 J
Step 9: KE = ½mv²
Step 10: KE = ½ × 8 × 15² = ½ × 8 × 225 = 900 J
Step 11: KE = ½mv²
Step 12: KE = ½ × 10 × 18² = ½ × 10 × 324 = 1620 J
Step 13: KE = ½mv²
Step 14: KE = ½ × 12 × 21² = ½ × 12 × 441 = 2646 J
Step 15: KE = ½mv²
Step 16: KE = ½ × 14 × 24² = ½ × 14 × 576 = 4032 J
Step 17: KE = ½mv²
Step 18: KE = ½ × 16 × 27² = ½ × 16 × 729 = 5832 J
Step 19: KE = ½mv²
Step 20: KE = ½ × 18 × 30² = ½ × 18 × 900 = 8100 J
Step 21: KE = ½mv²
Step 22: KE = ½ × 20 × 33² = ½ × 20 × 1089 = 10890 J
Step 23: KE = ½mv²
Step 24: KE = ½ × 22 × 6² = ½ × 22 × 36 = 396 J
Step 25: KE = ½mv²
Step 26: KE = ½ × 24 × 9² = ½ × 24 × 81 = 972 J
Step 27: KE = ½mv²
Step 28: KE = ½ × 26 × 12² = ½ × 26 × 144 = 1872 J
Step 29: KE = ½mv²
Step 30: KE = ½ × 28 × 15² = ½ × 28 × 225 = 3150 J
Step 31: KE = ½mv²
Step 32: KE = ½ × 30 × 18² = ½ × 30 × 324 = 4860 J
Step 33: KE = ½mv²
Step 34: KE = ½ × 2 × 21² = ½ × 2 × 441 = 441 J
Step 35: KE = ½mv²
Step 36: KE = ½ × 4 × 24² = ½ × 4 × 576 = 1152 J
Step 37: KE = ½mv²
Step 38: KE = ½ × 6 × 27² = ½ × 6 × 729 = 2187 J
Step 39: KE = ½mv²
Step 40: KE = ½ × 8 × 30² = ½ × 8 × 900 = 3600 J
Step 41: KE = ½mv²
Step 42: KE = ½ × 10 × 33² = ½ × 10 × 1089 = 5445 J
This problem applies energy. Understanding the underlying principle lets you solve similar problems with different values confidently.
❌ Mistake 1: Using the wrong units or forgetting to convert.
❌ Mistake 2: Applying the wrong formula for the given situation.
❌ Mistake 3: Rounding too early in the calculation.
See the step-by-step solution above for the complete answer.
This problem applies energy. Understanding the underlying principle lets you solve similar problems with different values confidently.